A) When a falling meteoroid is at a distance above the Earth\'s surface of 2.90

Question

A) When a falling meteoroid is at a distance above the Earth's surface of 2.90 times the Earth's radius, what is its acceleration due to the Earth's gravitation?
? m/s2 towards earth

When a falling meteoroid is at a distance above the Earth's surface of 2.90 times the Earth's radius, what is its acceleration due to the Earth's gravitation? ? m/s2 towards earth The free-fall acceleration on the surface of Neptune is about one and one half times that on the surface of the Earth. The radius of Neptune is about 3.50 RE (RE = Earth's radius = 6.4 times 106 m). Find the ratio of their average densities, ?Neptune/?Earth.

Explanation / Answer

A)

force and acceleration is inversely to the square of the distance.

If it is 2.9R from the surface, it is 3.9R from the center.

so a = 9.8/3.9

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