A block with a mass of 1.00kg is forced against a horizontal spring of negligibl

Question

A block with a mass of 1.00kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.05 m as shown in the figure above. When released, the block moves on a horizontal tabletop for 1.00m before comming to rest. The spring constant is 600N/m. What is the coefficient of kinetic friction uk between the block and the table top?

the answer is uk=7.65x10^-2

Please show how to work it. Answer with the most detail gets the points.

A block with a mass of 1.00kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.05 m as shown in the figure above. When released, the block moves on a horizontal tabletop for 1.00m before comming to rest. The spring constant is 600N/m. What is the coefficient of kinetic friction uk between the block and the table top? the answer is uk=7.65times10^-2 Please show how to work it. Answer with the most detail gets the points.

Explanation / Answer

0.5kx^2 = 0.5mv^2

v= 1.225m/s

decceleration,a = uk *m*g = 9.8*uk

v^2 = 2*a*s = 2*9.8*uk*1

uk = 7.65x10^-2

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