A Carnot refrigerator operating between -30.0 ? C and + 20.0 ? C extracts heat f

Question

A Carnot refrigerator operating between -30.0

?C and + 20.0?C extracts heat from the cold reservoir at the rate 100J/s . What are (a) the coefficient of performance of this refrigerator, (b) the rate at which work is done on the refrigerator and (c) the rate at which heat is exhausted to the hot side?

Part A. What is the coefficient of performance of this refrigerator?

Part B. What is the rate at which work is done on the refrigerator?

Part C. What is the rate at which heat is exhausted to the hot side?

Explanation / Answer

cop = T1/(T1-T2)

T1 =20+ 273K = 293K

T2 =-30 +273K =243K

COP =293/(293-243) = 5.86

C. COP =5.86 = Q2/(Q1-Q2)

Q2=100J/s

WE GET Q1 =117.06J/s

B. W=Q1-Q2 =17.06

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