Shown in the figure is an ideal spring hanging from a ceiling. When a mass 5.15

Question

Shown in the figure is an ideal spring hanging from a ceiling. When a mass 5.15 kg is attached to the spring (as shown in the middle system), the spring stretches by 0.0105 m. The mass is then pushed up from its equilibrium position 0.0210 m and released, as shown on the far right. Calculate the kinetic energy the mass possesses when passing through the equilibrium position.

The sum of the first and fifth terms of Arithmetic Progression equal to -, and the product of the third and fourth terms equal to -. Find the partial sum of the first 17 terms of this progression. Find the first three terms a1 a2,a3 of the Arithmetic Progression if we know that a1 + a3 +a5 = -12, and =80. Find the number of terms of Arithmetic Progression for which the partial sum equal to 112, the product of the second term and common difference equal to 30, and the sum of third and fifth terms equal to 32. Write the first three terms of this Progression. When dividing the ninth term on the second term of Arithmetic Progression We have 5. When dividing the thirteenth term on the sixth term we have 2 and the remainder is Find the first term and common difference. Find the first four terms a15a2,a3,tf4 of geometric progression where: ax + a4 = -49, and a2 + a3 = 14. Find third term of infinite geometric progression with the common ratio |r|

Explanation / Answer

k x = mg

x = m g / x = 5.15 * 9.8 / 0.0105

= 4806.66 N/m

w = sqrt[k/m] = sqrt[4806.66 / 5.15]

= 30.55 rad/s

v = A w = 0.0210 * 30.55

= 0.642 m/s

KE = 1/2 m v^2

= 0.5 * 5.15 * 0.642^2

= 1.06 J

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.