Questions 1,2, and 3 please! Thank you! How is the intensity of the unpolarized

Question

Questions 1,2, and 3 please!

Thank you!

How is the intensity of the unpolarized light affected when:

If the intensity of a lamp is I2 at a distance of 2 meters from the lamp, what is the intensity of the lamp at a distance of 6 meters? 8 meters? Show your work. (Your answer will be in terms of l2). Assuming ideal polarizers, how is the intensity of the unpolarized light affected when light passes through a vertical polarizer: light passes through a horizontal polarizer: light passes through two horizontal polarizers: light passes through a vertical and a horizontal polarizer; light passes through two polarizers that are at 60 degrees to each other: Show how you got your answer for part 2e.

Explanation / Answer

intensity follows inverse square law.

a) hence

at 6 m, I = I2 / 3^2 = I2 /9

at 8 m. I = I2 / 4^2 = I2 /16

b>

(a) Intensity becomes half

(b) Intensity becomes half

(c) since unpolarised light is horizontally polarised after passing through 1st polariser, the 2nd horizontal polariser has no effect.

Intensity becomes half

(d) since unpolarised light is vertically polarised after passing through 1st polariser, the 2nd horizontal polariser removes all the light

Hence Intensity becomes 0

(e) after 1st polariser, intensity is half

after 2nd polariser,

Intensity = cos^2 (60) * half

= one - eighth

3> after 1st polariser, intensity is half

after 2nd polariser,

Intensity = cos^2 (60) * half

= one - eighth of unpolarised

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