Water flows steadily from an open tank as shown in the figure. ( Figure 1 ) The
ID: 2255505 • Letter: W
Question
Water flows steadily from an open tank as shown in the figure. (Figure 1) The elevation of
Water flows steadily from an open tank as shown in the figure. (Figure 1) The elevation of point 1 is 10.0m , and the elevation of points 2 and 3 is 2.00m . The cross-sectional area at point 2 is 4.80 times 10?2m2 ; at point 3, where the water is discharged, it is 1.60 times 10?2m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. Assuming that Bernoulli's equation applies, compute the volume of water ?V that flows across the exit of the pipe in 1.00s . In other words, find the discharge rate ?V/?t. What is the gauge pressure pgauge at point 2?Explanation / Answer
use bernoulli's equation for 1 to 3, take v1 to equal zero and P3 = P1
P1/pg + z1 = P3/pg + v3^2/2g + z3
v3 = sqrt(2g(z1 - z3)) = sqrt(2*9.81(10 - 2)) = 12.53 m/s
Q = A3*v3 = .2005 m^3/s
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