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Two 0.500 kg blocks of wood are placed on a horizontal frictionless surface 2.00

ID: 2256018 • Letter: T

Question

Two 0.500 kg blocks of wood are placed on a horizontal frictionless surface 2.00 m apart a bullet having s mass of 10 g is firef horizontally st ghe first block the bullet is travelling at the speed of +400m/s to the right take the directiom if the bullet to be tje positive x direction the bullet passes the first block and imbeds itself to the second blovk tje speed of the first block immediatly after the bullet passes thru it is +6m/s

A. Sletch the situation after the bullet pased thru the furst block nd find the speed of the bullet at that point

B. Wht is the speed

Explanation / Answer


A) m*u = M1*V + m*v1

v1 = (mu-M1V)/m1 = ((0.01*400)-(0.5*6))/(0.01) = 100 m/s

B) mv1 = (m+M2)*V

V = m*v1/(m+M2) = (0.01*100)/(0.01+0.5)= 1.961 m/s

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