An m1 = 8.9 kg block and an m2 = 10.1 kg block, connected by a rope that passes

Question

An m1 = 8.9 kg block and an m2 = 10.1 kg block, connected by a rope that passes over a frictionless peg, slide on frictionless incline.

(a) Find the acceleration of the blocks and the tension in the rope.

a = ? m/s2

T = ? N

(b) The two blocks are replaced by two others of masses m1 and m2 such that there is no acceleration. Find whatever information you can about the masses of these two new blocks.

m1/m2 =?

can somoone please work out the problem and answer how we deal with having 2 variables in it?

An m1 = 8.9 kg block and an m2 = 10.1 kg block, connected by a rope that passes over a frictionless peg, slide on frictionless incline. Find the acceleration of the blocks and the tension in the rope. The two blocks are replaced by two others of masses m1 and m2 such that there is no acceleration. Find whatever information you can about the masses of these two new blocks.

Explanation / Answer

m2gsinA-m1gsinB=(m2+m1)a

10.1sin50-8.9sin40=(10.1+8.9)a

a=0.106 kg/m2

m2gsinA-T=m2a

T=6.67N

b)m2gsinA=m1sinB

m1/m2= sin50/sin40= 1.1917

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