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Part A Compute the torque developed by an industrial motor whose output is 175 k

ID: 2261168 • Letter: P

Question

Part A Compute the torque developed by an industrial motor whose output is 175kW at an angular speed of 4000rev/min .   ? =   N?m   SubmitMy AnswersGive Up Part B A drum with negligible mass and 0.600m in diameter is attached to the motor shaft, and the power output of the motor is used to raise a weight hanging from a rope wrapped around the drum. How heavy a weight can the motor lift at constant speed?   w =   N   SubmitMy AnswersGive Up Part C At what constant speed will the weight rise? Part A Compute the torque developed by an industrial motor whose output is 175kW at an angular speed of 4000rev/min .   ? =   N?m   SubmitMy AnswersGive Up Part A Compute the torque developed by an industrial motor whose output is 175kW at an angular speed of 4000rev/min .   ? =   N?m   SubmitMy AnswersGive Up   ? =   N?m     ? =   N?m   SubmitMy AnswersGive Up Part B A drum with negligible mass and 0.600m in diameter is attached to the motor shaft, and the power output of the motor is used to raise a weight hanging from a rope wrapped around the drum. How heavy a weight can the motor lift at constant speed?   w =   N   SubmitMy AnswersGive Up Part B A drum with negligible mass and 0.600m in diameter is attached to the motor shaft, and the power output of the motor is used to raise a weight hanging from a rope wrapped around the drum. How heavy a weight can the motor lift at constant speed?   w =   N   SubmitMy AnswersGive Up   w =   N     w =   N   SubmitMy AnswersGive Up Part C At what constant speed will the weight rise? Part C At what constant speed will the weight rise?   ? =   N?m  

Explanation / Answer

A) Power=Tourque x speed,125000=Tourque x 2Pi(4000/60)===>
Tourque=125000/(2Pi66.67)=
=298.41newton-meter
======================================...
B) W=298.41/(D/2)=298.41/0.15=1989.43newton...
======================================...
C) 2Pi(0.15)(4000/60)=62m/sec

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