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A block starts from rest at the top of a 17.0 degree inclined plane and encounte

ID: 2262165 • Letter: A

Question

A block starts from rest at the top of a 17.0 degree inclined plane and encounters a spring, of constant 480N/m, rigidly attached to the plane. If the block's mass is 5.75 kg and it compresses the spring by 12.0 cm, find the distance the block traveled before it encountered the spring. The coeffiient of friction between the block and the incline is 0.26.


I used the equation Ui+Ki+W=Uf+Kf to solve for "d"

Ui=(5.75 kg)(9.8m/s^2)(sin 17)(d+0.12 m)

Ki=0

W= -(0.26)(5.75 kg)(cos 17)(d+0.12 cm)

Uf=(1/2)(480 N/m)(0.12 cm)^2


Solved for d = 1.3 m or 130 cm


I was wondering if it is correct to use the distance + the compress spring (d+ 0.12 cm) as the total length or should I just use d?


Explanation / Answer

I have solved this type of problem the spring will not make sence if the ques would have been about the d from release point to the point of encounte. It should be till it stops and that will happen when the spring comresses maximum.

Delta U = 5.75 * 9.8* sin17 * d

Ki = 0 = Kf

Spring Energy = 0.5*480*0.12*0.12

W = - 0.26 *5.75*cos17* d

Equate to get, d

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