You are able to hold out your arm in an outstretched horizontal position because

Question

You are able to hold out your arm in an outstretched horizontal position because of the action of the deltoid muscle. Assume the humerus bone has a mass M1=3.6kg, length L=0.66m and its center of mass is a distance L1=0.33m from the scapula. (For this problem ignore the rest of the arm.) The deltoid muscle attaches to the humerus a distance L2=0.15m from the scapula. The deltoid muscle makes an angle of ?=17? with the horizontal, as shown. (Figure 1) (Figure 2) Use g=9.8m/s2throughout the problem.

Explanation / Answer

A:

Take the moments about the attachment point to the scapula:

T*Sin(17)*.15 - 3.6*9.8* 0.33 = 0

T*Sin(17)*.15 = 3.6*9.8*0.33

T = 3.6*9.8*.33/(.15*Sin(17)) = 265N

B:

Take the sum of the forces in the "y" direction:

3.6*9.8 - 265*Sin(17) + F_sy = 0

F_sy = 265*Sin(17) - 3.6*9.8 = 42.3 N (downward)

C:

Take the sum of the forces in the "x" direction:

T*Cos(17) - F_sx = 0

F_sx = T*Cos(17) = 265*Cos(17) = 253.4 N away from the body

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