Find the resultant magnetic force exerted by the long wire on the square current

Question

Find the resultant magnetic force exerted by the long wire on the square current loop in the figure below if I1 = 7.68 A and I2 = 3.84 A. The edge length of the square is 21.6 cm, and the distance from the long wire to the closest edge of the loop is 4.95 cm.

Find the resultant magnetic force exerted by the long wire on the square current loop in the figure below if I1 = 7.68 A and I2 = 3.84 A. The edge length of the square is 21.6 cm, and the distance from the long wire to the closest edge of the loop is 4.95 cm.

Explanation / Answer

magnetic force on a wire of length l is given by F - ilB sin theta

here the sides of squares form two parallel wires at two different distances

so Fnet = (B1-B2)*I2*L

= (uo*I1*I2*L/2pi)*((1/0.0495)-(1/(0.0495+0.216)

F = 2*10^-7*7.68*3.84*((1/0.0495)-(1/(0.0495+0.216)))

= 96.94 *10^-6 N

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