A 2.5 k g block slides along a frictionless surface at 1.7 m / s . A second bloc

ID: 2264030 • Letter: A

Question

A 2.5kg block slides along a frictionless surface at 1.7m/s . A second block, sliding at a faster 4.1m/s , collides with the first from behind and sticks to it. The final velocity of the combined blocks is 3.0m/s . What was the mass of the second block?
A 2.5kg block slides along a frictionless surface at 1.7m/s . A second block, sliding at a faster 4.1m/s , collides with the first from behind and sticks to it. The final velocity of the combined blocks is 3.0m/s . What was the mass of the second block?

Explanation / Answer

Here Momentum remains Conserved

Inital Momentum = Final Momentum

Therefore

2.5*1.7 + M*4.1 = (2.5+M)*3

M = 2.95455 Kg

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A 2.5 k g block slides along a frictionless surface at 1.7 m / s . A second bloc

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