A 2.360 kg block of wood rests on a steel desk. The coefficient of static fricti

Question

A 2.360 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is ?s = 0.605 and the coefficient of kinetic friction is ?k = 0.155. At time t = 0, a force F = 8.61 N is applied horizontally to the block. State the force of friction applied to the block by the table at the following times:t = 0,t > 0.Consider the same situation, but this time the external force F is 17.4 N. Again state the force of friction acting on the block at the following times:t = 0,t > 0.

Explanation / Answer

maximum static friction force f=0.605*2.36*10=14.278N

since F is less than f

hence f=F=8.61N

in Case 2

f=0.155*2.36*10=3.658N

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