In one day, a 85 kg mountain climber ascends from the 1440 m level on a vertical

Question

In one day, a 85 kg mountain climber ascends from the 1440 m level on a vertical cliff to the top at 2360 m . The next day, she descends from the top to the base of the cliff, which is at an elevation of 1310 m .

a) What is her gravitational potential energy on the first day? If you choose the reference level for zero potential energy at:

a. the top of the cliff.

b. 1440 m level.

c. 1310 m level.

b) What is her change in gravitational potential energy on the first day?

c) What is her change in gravitational potential energy on the second day?

Explanation / Answer

Gravitational potential energy is =M*g*h (where g=9.82 m/s^2)

a)Gravitational Potential energy with

1. Refernce as top =85*9.82*(2360-2360)=0joules as he is on top that is reference

2. Refernce as 1440 m= 85*9.82*(2360-1440)+767924 joules

3.Referene as 1310m =85*9.82*(2360-1310)=876435 joules

b)chage in energy= 85*9.82*(2360-1440)=767924 JOULES

C)change in energy on 2nd day=85*9.82*(1310-2360)= -876435 joules

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