I can\'t get the correct answer for the direction of the vector. Please help and

Question

I can't get the correct answer for the direction of the vector. Please help and show work so I can understand my mistake.

Use the worked example above to help you solve this problem. Consider three point charges at the corners of a triangle, as shown in the figure above, where q1 = 6.48 times 10-9 C, q2 = -1.95 times 10-9 C, and q3 = 5.14 times 10-9 C. Find the components of the force 23 exerted by q2 on q3. F 23x = N F 23y = N Find the components of the force 13 exerted by q1 on q3. F13X = N F13y = N Find the resultant force on q3, in terms of components and also in terms of magnitude and direction. Fx = N Fy = N magnitude N direction degree counterclockwise from the +x-axis Using the same triangle, find the vector components of the electric force on q1 and the vector's magnitude and direction. (Use the charges given in the Practice It section.) Fx = N Fy = N magnitude N direction degree counterclockwise from the +x-axis

Explanation / Answer

direction = arctan (Fy / Fx) = arctan ( 5.41 / -9.58) = -29.45

For counter clockwise,

direction = -28.215 + 360 = 330.55

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