You have m coffee = 250g of hot coffee at T hot coffee = 90 Physical System: cof
ID: 2270329 • Letter: Y
Question
You have mcoffee = 250g of hot coffee at Thot coffee = 90
Physical System: coffee, ice/water beginning: coffee 90 degree C ice -28 degree C end: coffee/water 0 degree C Physical System: coffee, ice/water beginning: coffee 90 degree C ice -28 degree C end: coffee/water 0 degree C Physical System: coffee, ice/water beginning: coffee 90 degree C ice -28 degree C end: coffee/water 0 degree C Delta coffee thermal + Delta E ice/water bond + Delta E ice/water thermal = Q Delta coffee thermal + Delta E ice/water bond + Delta E ice/water thermal = 0 Delta coffee thermal = Delta E ice/water bond + Delta E ice/water thermal Delta coffee thermal + Delta E ice/water bond = Delta E ice/water thermal + QExplanation / Answer
a)
dE coffee + de Ice/water bond + dE ice water/thermal = 0
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