Electric potential at the midpoint of two hydrogen atoms. http://jilawww.colorad

Question

Electric potential at the midpoint of two hydrogen atoms.

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Assume that the partial negative charge on the oxygen atom is Q1 = -1.056 x 10-19 C, the angle at the oxygen atom is &Theta = 104.2o and the distance between the oxygen and the hydrogen atoms is d = 92.2 x 10-9 m. What is the potential at the midpoint between the two hydrogen atoms?

Assume that the partial negative charge on the oxygen atom is Q1 = -1.056 x 10-19 C, the angle at the oxygen atom is = 104.2o and the distance between the oxygen and the hydrogen atoms is d = 92.2 x 10-9 m. What is the potential at the midpoint between the two hydrogen atoms?

Explanation / Answer

Vnet is same as Electric potential due to Oxygen atom ,

V = 9*10^9*-1.056*10^-19) / (92.2*10^-9*sin(104.2/2))

V = -0.0106772 Volt

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