A uniform electric field with a magnitude of 1000 N/C points in the negative x -

Question

A uniform electric field with a magnitude of  1000 N/C points in the negative x-direction, as shown in the figure below, where L = 0.8 cm.

A uniform electric field with a magnitude of 1000 N/C points in the negative x - direction, as shown in the figure below, where L = 0.8 cm. What is the difference in electric potential, ?V = VB ? VA, between points A and B? What is the difference in electric potential, ?V = VB ? VC, between points B and C? What is the difference in electric potential, ?V = VC ? VA, between points C and A? From the information given in this problem, is it possible to determine the value of the electric potential at point A? If so, determine VA; if not, enter "999".

Explanation / Answer

E= V/d where d is the distance in the direction of the electric field

(a) Vb-Va = zero since the electric field is in the direction perpendicular to the distance AB so Va=Vb
(b) Vb-Vc = -E*4L = -1000*4*(0.8)/100 =
(c) Vc-Va = E*4L = 1000*4*(0.8)/100 =

d)None of the actual potentials cannot be calculated with the given information. You need to know one of the other potentials before VA can be calculated.

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