A car traveling at a constant speed of 19 m/s passes an intersection at time t =

Question

A car traveling at a constant speed of 19 m/s passes an intersection at time t = 0. A second car traveling at a constant speed of 29 m/s in the same direction passes the same intersection 5.4 s later.

A car traveling at a constant speed of 19 m/s passes an intersection at time t = 0. A second car traveling at a constant speed of 29 m/s in the same direction passes the same intersection 5.4 s later. Determine when the second car will overtake the first. How far from the intersection will the two cars be when they pull even? Where is the first car when the second car passes the intersection?

Explanation / Answer

B) 19 * (x + 5.4) = 29 * X

19 * 5.4 = 10*x

x = 10.26 sec

Distance = 297.54 metres

C) Distance = 19 * 5.4 = 102.6 metre

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