A car takes 14 s to go from v = 0 to v = 70 m/s at approximately constant accele

Question

A car takes 14 s to go from v = 0 to v = 70 m/s at approximately constant acceleration. If you wish to find the distance traveled using the equation d = 1/2 at2, what value should you use for a?
m/s2

23.–/1 points Hewitt11 3.P.005.My Notes |
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Surprisingly, very few athletes can jump more than 2.2 ft (0.66 m) straight up. Use d = 1/2 gt2 and solve for the time one spends moving upward in a 2.2 foot vertical jump. Then double it for the "hang-time" -- the time one's feet are off the ground.

Explanation / Answer

Acceleration = delta v / delta t = 70 / 14 = 5

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