A car sits in an entrance ramp to a freeway, waiting for a break in the traffic.

Question

A car sits in an entrance ramp to a freeway, waiting for a break in the traffic. The driver sees a small gap between a van and an 18-wheel truck and accelerates with constant acceleration along the ramp and onto the freeway. The car starts from rest, moves in a straight line, and has a speed of 18.0m/s when it reaches the end of the ramp, which has length 119m .

Part A

What is the acceleration of the car?

Part B

How much time does it take the car to travel the length of the ramp?

Part C

The traffic on the freeway is moving at a constant speed of 18.0m/s . What distance does the traffic travel while the car is moving the length of the ramp?

Explanation / Answer

(a) v^2 = 2*a*d

a = v^2/(2*d)

a = (18 m/s)^2/(2*119 m)

a = 1.36m/s^2

(b) a = v/t

t = v/a

t = (18 m/s) / (1.36 m/s^2)

t = 13.22 s

(c) d = v*t

d = 18 m/s * 13.22 s

d = 238 m

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