A car sits in an entrance ramp to a freeway, waiting for a break in the traffic.

Question

A car sits in an entrance ramp to a freeway, waiting for a break in the traffic. The driver accelerates with constant acceleration along the ramp and onto the freeway. The car starts from rest, moves in a straight line, and has a speed of 40 m/s (89 mi/h) when it reaches the end of the 115 m long ramp. What is the acceleration of the car? m/s How much time does it take the car to travel the length of the ramp? S The traffic on the freeway is moving at a constant speed of 40 m/s. What distance does the traffic travel while the car is moving the length of the ramp? m

Explanation / Answer

vi = 0
vf = 40 m/s
Length of ramp , d = 115 m

vf^2 = vi^2 + 2*a*d
40^2 = 0 + 2*a*115
a = 6.96 m/s^2

(b)
vf = vi + a*t
40 = 0 + 6.96 * t
t = 5.75 s

(c)
Distance travelled by traffic, = 5.75 * 40 = 230 m

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