A car on a flat road accelerates from rest at a constant rate and covers a dista

Question

A car on a flat road accelerates from rest at a constant rate and covers a distance of 100 m in 6 s. The mass of the car is 1000 kg.

What is the acceleration of the car? m/s2

What is the net force on the car? N

The car is now loaded with heavy equipment and has a NEW total mass of 1400 kg.
If the same net force is applied to the car as calculated above, then what would be the new acceleration of the car? m/s2

With this new acceleration, how much time would it take the (heavier) car to travel 100 m starting from rest? s

What would be the speed of the (heavier) car when it reaches this point? m/s

Explanation / Answer

Applying d = v0 t + a t^2 /2

100 = 0 + a(6^2)/2

a = 5.56 m/s^2 ........Ans

F = m a = 1000x 5.56

F = 5555.6 N .......Ans

a = F/m

a = 5555.56 / 1400 = 3.97 m/s^2 ..........Ans

100 = 0 + 3.97 t^2 /2

t = 7.10 sec .........Ans

v = v0 + a t

v = 0 + (3.97 x 7.10) = 28.2 m/s ........Ans

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