A car on a flat road accelerates from rest at a constant rate and covers a dista

Question

A car on a flat road accelerates from rest at a constant rate and covers a distance of 100 m in 7 s.
The mass of the car is 1200 kg.

What is the acceleration of the car?  m/s2

What is the net force on the car?  N

The car is now loaded with heavy equipment and has a NEW total mass of 1600 kg.
If the same net force is applied to the car as calculated above, then what would be the new acceleration of the car?  m/s2

With this new acceleration, how much time would it take the (heavier) car to travel 100 m starting from rest?  s

What would be the speed of the (heavier) car when it reaches this point?  m/s

Explanation / Answer

d = v0 t + a t^2 /2

100 = 0 + a (7^2)/ 2

a = 4.08 m/s^2 .........Ans

F = m a= 1200 x 4.08

F = 4898 N ........Ans

a = F/ m = 4898 / 1600 = 3.06 m/s^2 ..........Ans

100 = 0 + 3.06 t^2 /2

t = 8.08 sec .......Ans

v = v0 + a t =0 + (8.08 x3.06)

v = 24.7 m/s ...........Ans

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