A 81.8-? resistor is connected in parallel with a 107.9-? resistor. This paralle
ID: 2273525 • Letter: A
Question
A 81.8-? resistor is connected in parallel with a 107.9-? resistor. This parallel group is connected in series with a 22.4-? resistor. The total combination is connected across a 16.4-V battery. Find (a) the current and (b) the power dissipated in the 107.9-? resistor.
Explanation / Answer
81.8 parallel with 107.9 => 81.8*107.9 / (81.8+107.9) = 46.53
46.53 series with 22.4 => 46.53 + 22.4 = 68.93
a)
i = V/R = 16.4/68.93 = 0.238 A
b)
current in 107.9 => 0.238*81.8/ (81.8+107.9) = 0.103 A
power dissipated = i^2 * R = (0.103)^2 * 107.9 = 1.145 W
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