(a) What is the speed of the ? -particle? (b) What is the magnitude of the magne
ID: 2274324 • Letter: #
Question
(a) What is the speed of the ?-particle?
(b) What is the magnitude of the magnetic force on it?
(c) What is the radius of its circular path?
Please show work.
An ?-particle has a charge of +2e and a mass of 6.64 ? 10-27 kg. It is accelerated from rest through a potential difference that has a value of1.06 106 V and then enters a uniform magnetic field whose magnitude is 3.10 T. The ? -particle moves perpendicular to the magnetic field at all times. What is the speed of the ?-particle? What is the magnitude of the magnetic force on it? What is the radius of its circular path?Explanation / Answer
V is potential difference
v is velocity of ? particle
m is mass and q is its charge
a charged particle subjected to pd will have potential energy qV and is equal to kinetic energy
a) v = sqrt(2qV/M) = sqrt( 2* 1.6 *10^-19 * 1.06 *10^6 /6.64 *10^-27) = 7.15 *10^6 m/s
b) F = qvB = 2*1.6 *10^-19 * 7.15 *10^6 * 3.1 = 7.09 *10^-12 N
c) r = mv/qB = 6.64 *10^-27 * 7.15 *10^6 /2*1.6*10^-19 * 3.1 = 0.048 m
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