(a) What is the speed of the ? -particle? _________ m/s (b) What is the magnitud

Question

(a) What is the speed of the ?-particle? _________ m/s

(b) What is the magnitude of the magnetic force on it? ____________ N

(c) What is the radius of its circular path? ____________ m

An ?-particle has a charge of +2e and a mass of 6.64 10-27 kg. It is accelerated from rest through a potential difference that has a value of 1.40 106 V and then enters a uniform magnetic field whose magnitude is 3.70 T. The ?-particle moves perpendicular to the magnetic field at all times. What is the speed of the ?-particle? _________ m/s What is the magnitude of the magnetic force on it? ____________ N What is the radius of its circular path? ____________ m

Explanation / Answer

a) eV = 1/2 mv^2

v = sqrt( 2 e V/m) = sqrt(2*2*1.6E-19*1.4E6/6.64E-27)=1.16E7 m/s

b) F = q v B = 2*1.6E-19*1.16E7*3.7=1.37E-11 N

c) q v B = mv^2/r

r = mv/(q B) = 6.64E-27*1.16E7/(2*1.6E-19*3.7)=0.065 m

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