?1= 3.4 uC/cm ?2= - 10.2 uC/cm a= 0.098m h=0.08m 1) What is the new value for E
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Question
?1= 3.4 uC/cm
?2= - 10.2 uC/cm
a= 0.098m
h=0.08m
1) What is the new value for Ex(P), the x-component of the electric field at point P?
2) What is the total flux ? that now passes through the cylindrical surface? Enter a positive number if the net flux leaves the cylinder and a negative number if the net flux enters the cylnder.
3) The initial infinite line of charge is now moved so that it is parallel to the y-axis at x = -4.9cm.
What is the new value for Ex(P), the x-component of the electric field at point P?
4) What is the total flux ? that now passes through the cylindrical surface? Enter a positive number if the net flux leaves the cylinder and a negative number if the net flux enters the cylnder.
What is the new value for Ex(P), the x-component of the electric field at point P What is the total flux ? that now passes through the cylindrical surface? Enter a positive number if the net flux leaves the cylinder and a negative number if the net flux enters the cylinder. The initial infinite line of charge is now moved so that it is parallel to the y-axis at x = -4.9cm. What is the new value for Ex(P), the x-component of the electric field at point P? What is the total flux ? that now passes through the cylindrical surface? Enter a positive number if the net flux leaves the cylinder and a negative number if the net flux enters the cylinder.Explanation / Answer
?1= 3.4 uC/cm = 3.4e-6/(1e-2) C/m = 3.4e-4 C/m
?2= -10.2 uC/cm = -10.2e-6/(1e-2) C/m = -10.2e-4 C/m
a= 0.098 m
h=0.08 m
1) What is the new value for Ex(P), the x-component of the electric field at point P?
Ex(P) = E1 - E2
Ex(P) = lamda1/(2 pi a epsilon0) - lamda2/(2 pi (a/2) epsilon0)
Ex(P) = (3.4e-4)/(2*3.1416*0.098*8.85e-12) - (10.2e-4)/(2*3.1416*(0.098/2)*8.85e-12)
Ex(P) = -3.12 x 10^8 N/C
2) What is the total flux ? that now passes through the cylindrical surface? Enter a positive number if the net flux leaves the cylinder and a negative number if the net flux enters the cylnder.
flux = (q_net)/(epsilon0)
flux = (lambda1 + lambda2)*h/(epsilon0)
flux = (3.4e-4-10.2e-4)*0.08/(8.85e-12)
flux = -6.15 x 10^6 N.m2/C
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3)
Ex(P) = E1 - E2
Ex(P) = lamda1/(2 pi (3a/2) epsilon0) - lamda2/(2 pi (a/2) epsilon0)
Ex(P) = (3.4e-4)/(2*3.1416*(3*0.098/2)*8.85e-12) - (10.2e-4)/(2*3.1416*(0.098/2)*8.85e-12)
Ex(P) = -3.33 x 10^8 N/C
4)
flux = (q_net)/(epsilon0)
flux = (lambda1 + lambda2)*h/(epsilon0)
flux = (3.4e-4-10.2e-4)*0.08/(8.85e-12)
flux = -6.15 x 10^6 N.m2/C
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