Three charged particles are placed at each of three corners of an equilateral tr

Question

Three charged particles are placed at each of three corners of an equilateral triangle whose sides are of length 3.4cm . Two of the particles have a negative charge: q1 = -8.1nC and q2 = -16.2nC . The remaining particle has a positive charge, q3 = 8.0nC . What is the net electric force acting on particle 3 due to particle 1 and particle 2?

Find the net force ?F? 3 acting on particle 3 due to the presence of the other two particles. Report you answer as a magnitude ?F3 and a direction ? measured from the positive x axis.

Explanation / Answer

force due to q1 = [9*10^9 * 8.1*8 * 10^-18 / 0.034^2] *[ cos 60 i^ + sin 60 j^ ]

F1 = 5.044983 * 10^-4 * [ 0.5i^ + 0.866 j^ ]

so.. F1 = 2.5224915 * 10^-4 i^ + 4.369 *10^-4 j^ N

force due to q2 = [9*10^9 * 16.2*8 * 10^-18 / 0.034^2] *[ i^]

F2 = 10.089966 * 10^-4 * i^

so... total force F3 = F1 + F2 = 2.5224915 * 10^-4 i^ + 4.369 *10^-4 j^ + 10.089966 * 10^-4

so... F3 = 12.6124575 * 10^-4 i^ + 4.369 *10^-4 j^

so.. magnitude of F3 = 10^-4 * sqrt ( 12.6124575^2 + 4.369^2 ) = 13.34774 * 10^-4 N

for getting the angle I will need the figure.. please insert the figure

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