A converging lens of focal length 7.550 c m is 20.5 c m to the left of a divergi

Question

A converging lens of focal length 7.550cm is 20.5cm to the left of a diverging lens of focal length -6.50cm . A coin is placed 18.2cm to the right of the diverging lens. A) Find the location of the coins final image (To the left of the converging lens) B) Find the magnification of the coins final image. A converging lens of focal length 7.550cm is 20.5cm to the left of a diverging lens of focal length -6.50cm . A coin is placed 18.2cm to the right of the diverging lens. A converging lens of focal length 7.550cm is 20.5cm to the left of a diverging lens of focal length -6.50cm . A coin is placed 18.2cm to the right of the diverging lens. A converging lens of focal length 7.550cm is 20.5cm to the left of a diverging lens of focal length -6.50cm . A coin is placed 18.2cm to the right of the diverging lens. A) Find the location of the coins final image (To the left of the converging lens) B) Find the magnification of the coins final image. A) Find the location of the coins final image (To the left of the converging lens) B) Find the magnification of the coins final image.

Explanation / Answer

(1/v + 1/u = 1/f)

First throught eh diverging lens:

(1/v = 1/-6.5 - (1/-18.2); v = 10.11 cm) to the right of the lens

Through the converging lens:

(1/v = 1/7.55 - 1/(-20.5-10.11); v = 6.06 cm) to the left of the converging lens, real image.

Magnification = v/u = (6.06+20.5)/18.2 = 1.459

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