(a) What is the magnitude of the average acceleration of a skier who, starting f

Question

(a) What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 5.22 m/s when going down a slope for 3.16 s? (b) How far does the skier travel in this time?

(a) Number Units                No units                            s                            m                            m/s                            m/s^2              What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 5.22 m/s when going down a slope for 3.16 s? How far does the skier travel in this time?

Explanation / Answer

V = u+at

acc = v/t = 5.22/3.16 = 1.6519 m/s^2

b) s = 1/2*a*t^2 = 0.5*1.6519*3.16^2 = 8.2476 m

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