The earth moves around the sun in a nearly circular orbit of radius 1.50 x 10 11

Question

The earth moves around the sun in a nearly circular orbit of radius 1.50 x 1011 m. During the three summer months (an elapsed time of 7.89 x 106 s), the earth moves one-fourth of the distance around the sun. (a) What is the average speed of the earth? (b)What is the magnitude of the average velocity of the earth during this period?

(a) Number Units No units The earth moves around the sun in a nearly circular orbit of radius 1.50 times 1011 m. During the three summer months (an elapsed time of 7.89 times 106 s), the earth moves one-fourth of the distance around the sun. (a) What is the average speed of the earth? (b)What is the magnitude of the average velocity of the earth during this period?

Explanation / Answer

a)

Circumference of the circle = 2? R.

One-fourth of the distance around the sun = [1/4]*. 2? R = ? R/2

average speed of the earth = Distance /time = ? R/[2t]

= ?* 1.50e11/ [2*7.89e6]= 29863m/s

b)

The displacement during this time is the length of the chord

=?[ 2R^2] = 1.414*R = 1.414*1.50e11 = 2.121e11m

Magnitude of Average velocity = 2.121e11/7.89e6

=26882m/s

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