The earth moves around the sun in a nearly circular orbit ofradius 1.50*10 11 m.

Question

The earth moves around the sun in a nearly circular orbit ofradius 1.50*1011 m. During the three summer months(an elapsed time of 7.89*106 s), the earth movesone-fourth of the distance around the sun. (a) What is theaverage speed of the earth? (b) What is the magnitude of theaverage velocity of the earth during this period? answer: 34km/h, due north The earth moves around the sun in a nearly circular orbit ofradius 1.50*1011 m. During the three summer months(an elapsed time of 7.89*106 s), the earth movesone-fourth of the distance around the sun. (a) What is theaverage speed of the earth? (b) What is the magnitude of theaverage velocity of the earth during this period? answer: 34km/h, due north

Explanation / Answer

Your equation should look similar to the following one: speed=d/t In this case the distance, d, is one-fourth of thecircumference of the circular path of the earth orbiting thesun d=1/4(c) a. so, (1.50*10^11m)/2(7.89*10^6s)= 2.99*10^4m/s b. speed = r/t 2(1.50*10^11m)/7.89*10^6s= 2.69*10^4 m/s

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