A charged particle is moving perpendicularly to a magnetic field B. Fill in the

Question

A charged particle is moving perpendicularly to a magnetic field B. Fill in the blank indicating the direction for the quantity missing in each option.

Use the diagram above for the directions of the various axes.
+x-x+y-y+z-z Negative Charge, Velocity: ???, B-Field: -z, Force: +y
+x-x+y-y+z-z Positive Charge, Velocity: +y, B-Field: ???, Force: -z
+x-x+y-y+z-z Positive Charge, Velocity: +y, B-Field: -z, Force: ???

A charged particle moves through a velocity selector at a constant speed in a straight line. The electric field of the velocity selector is 3.61E+3 N/C, while the magnetic field is 0.397 T. When the electric field is turned off, the charged particle travels on a circular path whose radius is 4.03 cm. Calculate the charge-to-mass ratio of the particle.

The solar wind is a thin, hot gas given off by the sun. Charged particles in this gas enter the magnetic field of the earth and can experience a magnetic force. Suppose a charged particle traveling with a speed of 9.08E+6 m/s encounters the earth's magnetic field at an altitude where the field has a magnitude of 1.30E-7 T. Assuming that the particle's velocity is perpendicular to the magnetic field, calculate the radius of the circular path on which the particle would move if it were an electron.

A charged particle is moving perpendicularly to a magnetic field B. Fill in the blank indicating the direction for the quantity missing in each option. Use the diagram above for the directions of the various axes. A charged particle moves through a velocity selector at a constant speed in a straight line. The electric field of the velocity selector is 3.61E+3 N/C, while the magnetic field is 0.397 T. When the electric field is turned off, the charged particle travels on a circular path whose radius is 4.03 cm. Calculate the charge-to-mass ratio of the particle. The solar wind is a thin, hot gas given off by the sun. Charged particles in this gas enter the magnetic field of the earth and can experience a magnetic force. Suppose a charged particle traveling with a speed of 9.08E+6 m/s encounters the earth's magnetic field at an altitude where the field has a magnitude of 1.30E-7 T. Assuming that the particle's velocity is perpendicular to the magnetic field, calculate the radius of the circular path on which the particle would move if it were an electron.

Explanation / Answer

1) Must use right hand rule. Do it first assuming a positive charge , If the change is negative then change the direction to its opposite (180 degrees away )

2)q/m = E/rB^2 = 3.61x10^3 / (4.03 x 10^-2 x 0.397^2) = 568500.393 Ckg^-1

3) F = qvB where q = charge, v = speed and B = magneitc field strength and assumes v is pependicular to B

Use m= 9.11x10^-31 kg for the electron and m = 1.6x10^-27 kg for the proton and you're done

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