A small 12.8 g plastic ball is tied to a very light 29.8 cm string that is attac
ID: 2276917 • Letter: A
Question
A small 12.8 g plastic ball is tied to a very light 29.8 cm
string that is attached to the vertical wall of a room. (See the figure (Figure 1) .) A uniform horizontal electric field exists in this room. When the ball has been given an excess charge of -1.50
?C
, you observe that it remains suspended, with the string making an angle of 17.4 degree with the wall.
http://session.masteringphysics.com/problemAsset/1267054/2/yg.17.57.jpg
A)Find the magnitude of the electric field in the room.
E= ........ N/C
A small 12.8 g plastic ball is tied to a very light 29.8 cm string that is attached to the vertical wall of a room. (See the figure (Figure 1) .) A uniform horizontal electric field exists in this room. When the ball has been given an excess charge of -1.50 ?C , you observe that it remains suspended, with the string making an angle of 17.4 degree with the wall. Find the magnitude of the electric field in the room.Explanation / Answer
electrostatic force, Fe = q*E = 1.5*10^-6 *E gravitational force, Fg = m*g = 12.8*10^-3* 9.8 = 0.12544 N tan(theta) = Fe/Fg => tan17.4 = (1.5*10^-6*E)/0.12544 => E = 26207.00877 N/C
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