The two wires shown in the figure below carry currents of I = 5.28 A in opposite

Question

The two wires shown in the figure below carry currents of I = 5.28 A in opposite directions and are separated by d0 = 9.60 cm.

1. Calculate the net magnetic field at a point midway between the wires. Use the direction into the page as the positive direction and out of the page as the negative direction.

2. Calculate the net magnetic field at point P1 - that is, d1 = 9.75 cm to the right of the wire on the right.

3. Calculate the net magnetic field at point P2 - that is, d2 = 21.9 cm to the left of the wire on the left.

The two wires shown in the figure below carry currents of I = 5.28 A in opposite directions and are separated by d0 = 9.60 cm. Calculate the net magnetic field at a point midway between the wires. Use the direction into the page as the positive direction and out of the page as the negative direction. Calculate the net magnetic field at point P1 - that is, d1 = 9.75 cm to the right of the wire on the right. Calculate the net magnetic field at point P2 - that is, d2 = 21.9 cm to the left of the wire on the left.

Explanation / Answer

The formula for the magnetic field from each wire is B = uI/2pir

For part 1, the B fields will add since they will be going in the same direction

B = 2(4pi X 10^-7)(5.28)/(2pi)(.048)

B = 4.4 X 10^-5 T

Part 2)

B = (4pi X 10^-7)(5.28)/(2pi)(.0975) - (4pi X 10^-7)(5.28)/(2pi)(.1935)

B = 5.37 X 10^-6 T

Part 3)

B = (4pi X 10^-7)(5.28)/(2pi)(.219) - (4pi X 10^-7)(5.28)/(2pi)(.315)

B = 1.47 X 10^-6 T

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