A 7.5?F capacitor is charged by a 140V battery and then is disconnected from the

Question

A 7.5?F capacitor is charged by a 140V battery and then is disconnected from the battery. When this capacitor (C1) is then connected to a second (initially uncharged) capacitor, C2 , the final voltage on each capacitor is 20V. What is the value of C2? [Hint: charge is conserved.]

A 7.5?F capacitor is charged by a 140V battery and then is disconnected from the battery. When this capacitor (C1) is then connected to a second (initially uncharged) capacitor, C2 , the final voltage on each capacitor is 20V. What is the value of C2? [Hint: charge is conserved.]

Explanation / Answer

Vfinal = (C1V1+C2V2)/(C1+C2)

20 = 140*3.5+ 0 /(3.5 +c2)

s0, C2 = 21 uF

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