1.A box is given a push so that it slides across the floor. How far will it go,
ID: 2279273 • Letter: 1
Question
1.A box is given a push so that it slides across the floor.
How far will it go, given that the coefficient of kinetic friction is 0.20 and the push imparts an initial speed of 3.9
m/s?
2. A block with mass mA = 12.0kg on a smooth horizontal surface is connected by a thin cord that passes over a pulley to a second block with mass mB= 6.0kg which hangs vertically. (Figure 1)
a.Determine the magnitude of the acceleration of the system.
b.If initiallymA is at rest 1.250mfrom the edge of the table, how long does it take to reach the edge of the table if the system is allowed to move freely?
c) IfmB= 1.0kg, how large must mA be if the acceleration of the system is to be kept at g/100?
Explanation / Answer
1)
acceleration = - u*g = -0.2*9.8 = -1.96 m/s^2
v^2 = u^2 + 2*a*s
0 = 3.9^2 - 2*1.96*s
s = 3.88 m
2)
a)
T = Ma * a
Mb*g - T = Mb*a
add both
Mb*g = (Ma + Mb)*a
a = Mb*g / (Ma + Mb) = 6*9.8/(12+6) = 3.267 m/s^2
b)
s = ut + 0.5*a*t^2
u =0
1.25 = 0.5*3.267 *t^2
t = 0.875 s
c)
a = Mb*g / (Ma + Mb)
g/100 = Mb*g / (Ma + Mb)
100 = (Mb+Ma)/Mb
100 = (1+Ma)/1
Ma = 100 -1 = 99 kg
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