The figure shows a parallel-plate capacitor with a plate area A = 7.39 cm 2 and

Question

The figure shows a parallel-plate capacitor with a plate area A = 7.39 cm2 and plate separation d = 9.98  mm. The left half of the gap is filled with material of dielectric constant ?1 = 8.60; the right  half is filled with material of dielectric constant ?2 = 11.0. What is the  capacitance?

The figure shows a parallel-plate capacitor with a plate area A = 7.39 cm2 and plate separation d = 9.98 mm. The left half of the gap is filled with material of dielectric constant ?1 = 8.60; the right half is filled with material of dielectric constant ?2 = 11.0. What is the capacitance?

Explanation / Answer

we can assume them as two capcitors in series
C1= e*8.6*7.39/ 4.99 = 11.2 pf

C2 = e*11*7.39/4.99 = 14.4 pf

C = 6.3 pf

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