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1.Determine the equivalent resistance between the points A and B for the group o

ID: 2280557 • Letter: 1

Question

1.Determine the equivalent resistance between the points A and B for the group of resistors in the drawing. Use R1 = 4 ?, R2 = 13 ?, and R3 = 6 ?.
Req = ?

?

Determine the equivalent resistance between the points A and B for the group of resistors in the drawing. Use R1 = 4 ?, R2 = 13 ?, and R3 = 6 ?. A 1.56-? resistor is connected across a 6.40-V battery. The voltage between the terminals of the battery is observed to be only 5.90 V. Find the internal resistance of the battery. Two capacitors are connected in parallel across the terminals of a battery. One has a capacitance of 2.0 mu F and the other a capacitance of 4.5 mu F. These two capacitors together store 5.70 times 10-5 C of charge. What is the voltage of the battery? Determine the equivalent capacitance between A and B for the group of capacitors in the drawing. Let C1 = 12 mu F and C2 = 6.0 mu F.

Explanation / Answer

1.


equivalent resistance


R2 and 6 ohms are in series


13+6 =19 ohms


9 ohms anr R3 are in parallel


9*6/(9+6) =3.6 ohms


3.6 ohms and 19 ohms are in parallel


3.6*19/(3.6+19) =3.03 ohms


3.03 and R1 are in series


3.03+4=7.03 ohms


7.03 and 20 are in parallel


Req =7.03*20/(7.03+20)


Req=5.2 ohms


2)


I=V/R =6.4/15.6


I=4.1 A


E=V+I*r


=>r=E-V/I =6.4-5.94.1


r=0.122 ohms


3)


equivalent capacitance


Ceq =C1+C2 =2+4.5


Ceq =6.5 uF


Voltage


V=Q/C =5.7*10^-5/6.5*10^-6


V=8.77 V


4)


24 ,C1=12 uF and 8 uF are in series


1/C =1/24 +1/12 +1/8


C=4 uF


4 uf and 4 uF are in parallel


4+4 =8 uF


5 uF ,8uF and C2=6 uF


1/Ceq =1/5 +1/8 +1/6


Ceq =2.034 uF



5)


a)


P=V^2/R


=>R=V^2/P


reistance of toaster


R_toaster=120^2/1500 =9.6 ohms


resistance of iron


R_iron=120^2/1060 =13.585 ohms


Resistance of ovenis


R_oven =120^2/1250


R_oven =11.52 ohsm


so equivalent resistance


1/Req =1/R_toaster +1/R_iron +1/R_oven


1/Req =1/9.6 +1/13.585 +1/11.52


Req =3.78 ohms


b)


I=V/Req =120/3.78


I=31.75 A


c)


the breaker will remain open



6)


R=pL/A


given L2=4L1


R1/R2 =L1/L2


18.9/R2 =L1/4L1


R2 =75.6 ohms

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