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You are a member of an alpine rescue team and must get a box of supplies, with m

ID: 2280890 • Letter: Y

Question

You are a member of an alpine rescue team and must get a box of supplies, with mass 3.00kg , up an incline of constant slope angle 30.0 so that it reaches a stranded skier who is a vertical distance 3.50m above the bottom of the incline. There is some friction present; the kinetic coefficient of friction is 6.00Ý102. Since you can't walk up the incline, you give the box a push that gives it an initial velocity; then the box slides up the incline, slowing down under the forces of friction and gravity. Take acceleration due to gravity to be 9.81m/s2 .


Use the work-energy theorem to calculate the minimum speed v that you must give the box at the bottom of the incline so that it will reach the skier.


I keep getting 8.91 m/s but it says that's wrong?

Explanation / Answer

final total energy = P.E. + K.E.

K.E. = 0 because velocity = 0 ( k.e. = .5 m v^2)

T.E. = mgh + 0 = (3)(9.81)(3.5) = 103.005


innitial t.e. = p.e. + k.e. = 0 + 0.5 (3)v^2


total energy is conserved


.5(3)(v^2) = (3)(9.81)(3.5)+ work done by friction. --- (1)

work done by friction = frictional force * distance = coeff of friction *m*g *d = 6x10^-2*3*9.81*3.5/cos30

plug this in equation 1 and solve for v