1.) Three charged particles are placed on a line like in the figure. Determine t
ID: 2282179 • Letter: 1
Question
1.) Three charged particles are placed on a line like in the figure. Determine the magnitude and direction of the net force acting on the Q1=50 ?C due to the other two particles.
a.) 3.6 x103 N directed toward the left
3.6 x103 N directed toward the right
3.6 x109 N directed toward the left
3.6 x109 N directed toward the right
2.) The total electric flux from a cubical box of side 45.0 cm is 5.61 x103 Nm2/C. What charge is enclosed in the box?
a.) 5.05 x10-13 C
4.96 x10-8 C
c.) 6.34 x1014 C
2.67 x106 C
3.) Two charges are separated by a distance d. If the distance is reduced by half, what does happen to the force between the charges?
it decreases by a factor of 4
it increases by a factor of 4
it decreases by a factor of 2
it increases by a factor of 2
4.) An electron is released in a uniform electric field, and it experiences an electric force of 4.26 x10--14 N directed toward the north. Find the magnitude and direction of the electric field.
7.71 x10-7 N/C directed north
2.66 x105 N/C directed south
3.72 x10-32 N/C directed south
5.85 x106 N/C directed north
a.) 3.6 x103 N directed toward the left
b.)3.6 x103 N directed toward the right
c.)3.6 x109 N directed toward the left
d.)3.6 x109 N directed toward the right
Explanation / Answer
Fnet = F12 - F13
Fnet = q1*((k*q2/r2^2)-(k*q3/r3^2))
Fnet = 50e-6*(((9e9*30e-6)/(0.06*0.06)) - ((9e9*10e-6)/(0.2*0.2)))
Fnet = 3.6 x10^3
b ) 3.6 x10^3 N directed toward the right
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Q = flux*eo = 5.61e3*8.85e-12
b.) 4.96 x10^-8 C
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F = k*q1*q2/r^2
F' = k*q1*q2/r'^2
r' = r/2
F' = k*q1*q2/r^2/4 = 4 *k*q1*q2/r^2
F' = 4*F
it increases by a factor of 4
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F = E*q
E = F/e = 4.26e-14/1.6e-19
b) 2.66 x105 N/C directed south
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