Consider a 71.0-kg man standing on a spring scale in an elevator. Starting from

Question

Consider a 71.0-kg man standing on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.82 m/s in 0.650 s. It travels with this constant speed for the next 5.00 s. The elevator then undergoes a uniform acceleration in the negative y direction for 1.60 s and comes to rest.

(a) What does the spring scale register before the elevator starts to move?
N

(b) What does the spring scale register during the first 0.650 s?
N

(c) What does the spring scale register while the elevator is traveling at constant speed?
N

(d) What does the spring scale register during the time it is slowing down?
N

Explanation / Answer

a) N = m*g = 71*9.8 = 695.8 N

b) a = v/t = 1.82/.65 = 2.8 m/s^2

N2 = m*(g+a) = 894.6 N

c) N = m*g = 695.8 N

d) a2 = 1.82/1.6 = -1.14 m/s^2

N3 = m*(g-a) = 776.74 N

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