Consider a 73.0-kg man standing on a spring scale in an elevator. Starting from

Question

Consider a 73.0-kg man standing on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.50 m/s in 0.600 s. It travels with this constant speed for the next 5.00 s. The elevator then undergoes a uniform acceleration in the negative y direction for 1.60 s and comes to rest. What does the spring scale register before the elevator starts to move? N What does the spring scale register during the first 0.600 s? What does the spring scale register while the elevator is traveling at constant speed? N What does the spring scale register during the time it is slowing down? N A car is traveling at 53.0 mi/h on a horizontal highway. If the coefficient of static friction between road and tires on a rainy day is 0.101, what is the minimum distance in which the car will stop? What is the stopping distance when the surface is dry and mu s = 0.602? m

Explanation / Answer

1)716.13 Newtons (just the weight)
182.5 N + 716.13 N = 898.63 newtons (acceleration force +weight)
716.13 Newtons (just the weight because constant velocity)
716.13 N - 68.43N = 647.7 newtons (weight minus acceleration force)

2)a) You need the acceleration required to bring the car to rest, from Newton

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