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https/ s2.lite.msu.edu c/76/04 bed 446a7335 9bfa883 773 bd672 9a45 97c 8864e820d990do 5295 3b40488 9197 c3968c94 32344a (Student section: 003 PHY 184 Spring 2015 (002+003) h Raymond Help Log Main Menu Contents Grades HW 02 (02/02 M 10 PM) Electric field of a charged sphere Time back A nonconducting solid sphere of radius 2.90 cm carries a uniformly distributed positive charge of 6.80x10 9 C. Calculate the magnitude of the electric field at a point 1.30 cm away from the center of the sphere (1.049*10 4)N/C This distance is still within the sphere. You have to integrate the charge up to this distance Submit Answer Incorrect. T 2/12 Previous Tries Calculate the magnitude of the electric field at a point 3.80 cm away from the center of the sphere (7.55 N/C This distance now is outside the sphere Submit Answer Incorrect. Tries 1/12 Previous Tries Assume that the sphere is conducting. Calculate the magnitude of the electric field at a point 1.30 cm away from the center of the sphere 0 N/C You are correct Previous Tries Your receipt no s 155-5848 Goo Calculate the magnitude of the electric field for the conducting sphere at a point 3.80 cm away from the center of the sphere N/C Again Gauss's Law. What do you know about the field outside a spherically symmetric charge distribution. Submit Answer Incorrect. Tries 3/12 Previous Tries Threaded View Chronological View Other V NEW Mark NEW posts no longer n NEW cant seem to get the right answer.. Anonymous 1 Reply (Sat Jan 31 01:57:58 pm 2015 (EST)) I am using the equation E qr/ 4 pi Ething (R 3) he bigg d Ething y help 8.99x10 9 NEW Re: cant seem to get the right answer.. Stefan Andrew Trentacosta Reply (Sat Jan 31 03:07:23 pm 2015 (EST)) The equation you're using is wrong. go look at Professor Nagy's Conducting vs Nonconducting Sphere hint page. That should hopefully put you on the right track Feb 1 02:04:15 p NEW Joseph Raymond Zajac Reply (S 2015 (EST part d g KQVr 2 rking he prop ked My Display All p 2. N NEW Change Threaded View Chronological View Other V My general prefere n what is marked as NEW Mark NEW posts no longer n :24 PM 2/1/20Explanation / Answer
1) qenc = Venc/ V q
V = 4/3 pi r^3
so qenc = q r^3/R^3 = 6.8E-9*1.3^3/2.9^3= 6.13E-10 C
E = k q/r^2 = 9.0E9*6.13E-10/0.013^2= 3.26E4 N/C
2)
now qenc = q
E = k q/r^2 = 9.0E9*6.8E-9/0.038^2= 4.24E4 N/C
4) same as part 2) 4.24E4 N/C
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