A 0.50- ? F and a 1.4- ? F capacitor ( C 1 and C 2, respectively) are connected

Question

A 0.50-?F and a 1.4-?F capacitor (C1 and C2, respectively) are connected in series to a 17-Vbattery.

1. Calculate the potential difference across each capacitor. Express your answers using two significant figures separated by a comma.

2. Calculate the charge on each capasitor. Express your answers using two significant figures separated by a comma.

3. Calculate the potential difference across each capacitor assuming the two capacitors are in parallel. Express your answers using two significant figures separated by a comma.

4. Calculate the charge on each capasitor assuming the two capacitors are in parallel. Express your answers using two significant figures separated by a comma.

Explanation / Answer

when capacitors are in series

net capacitance Cs=(C1+C2)/C1C2

Cs=(0.5+1.4)/(0.5*1.4)

when capacitores are in series,charge on both the capacitors will be same

part 1)

Cs=Q/V

so Q=CsV

part 2)

but V1 and V2 will be different for both the capacitors

we can find both

V1=Q/C1

V2=Q/C2

part 3)

when capacitors are in parallel, net capacitance

Cp=C1+C2

Cp=0.5+1.4

in parallel potential is same on both the capacitors that is V=17 V

part 4)

charge will be different

Q1=C1V

Q2=C2V

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