IP Point charges +4.4 ? C and -2.2 ? C are placed on the x axis at (15m , 0) and

Question

IP Point charges +4.4?C and -2.2?C are placed on the x axis at (15m , 0) and (-15m , 0), respectively.

Part A

There is one point on the x axis between the two charges where the potential vanishes. Is this point closer to the +4.4?C charge or closer to the -2.2?C charge?

There is one point on the exttip{x}{x} axis between the two charges where the potential vanishes. Is this point closer to the +4.4{ m mu C} charge or closer to the -2.2{ m mu C} charge?

on the halfway between them

Part C

Find the point referred to in part A.

on the halfway between them

Part C

Find the point referred to in part A.

Explanation / Answer

Closer to q2 ie 2.2

V1=kq1/r1

V2=kq2/r2

q1/r1=q2/r2

q1/(30-x)=q2/x

30-x/x=q1/q2

30/x-1=2

30/x=3

x=10m from q2 at -5m

it is 20 m from q1

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