A ball is tossed from an upper-story window of a building. The ball is given an

Question

A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 9.30 m/s at an angle of 16.0 degree below the horizontal. It strikes the ground 5.00 s later. (a) How far horizontally from the base of the building does the ball strike the ground? (b) Find the height from which the ball was thrown. Work only with the vertical components of these quantities. This part of the problem is then a 1-dimensional free-fall example. (c) How long does it take the ball to reach a point 10.0 m below the level of launching?

Explanation / Answer

I see you have part A, so lets start with part B.

Part B)

Apply d = vot + .5at2

The initial velocity in the y direction is 9.3(sin 16) = 2.56 m/s downward

d = (2.56)(5) + (.5)(9.8)(5)2

d = 135 m

Part C)

Lets find the speed it will have vertically after traveling 100 m

vf2 = vo2 + 2ad

vf2 = (2.56)2 + 2(9.8)(100)

vf = 44.3 m/s

Then vf = vo + t

44.3 = 2.56 + 9.8(t)

t = 4.26 sec

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