two large parallel conducting plates are 12cm apart and have equal but opposite
ID: 2289660 • Letter: T
Question
two large parallel conducting plates are 12cm apart and have equal but opposite charges on their facing surfaces. A) an elesctrostatic forces of 4.0x10^-15 N acts on a proton midway between the plates. find the electric field at the protons position. B) what is the potential difference the plates? C) A dipole consists of a +-e charges seperated by 80 pm(pico+10^-12). How much work is required to turn the dipole from being aligned with the E fiield to be perpendicular to it? answer in electron volts
Explanation / Answer
part a)
Electric field at the protons position=E=F/e
where e is chareg on proton
part b)
since E is constant in between plates
and spacing between plates=d
so potential difference V=E/d
part c)
work done=change in potential energy
U=-pEcosa
in first case
a=0
in second case a=90
dU=0-(-pE)=pE
W=pE=qsE
q=e
s=10-12
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