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two large parallel conducting plates are 12cm apart and have equal but opposite

ID: 2289660 • Letter: T

Question

two large parallel conducting plates are 12cm apart and have equal but opposite charges on their facing surfaces. A) an elesctrostatic forces of 4.0x10^-15 N acts on a proton midway between the plates. find the electric field at the protons position. B) what is the potential difference the plates? C) A dipole consists of a +-e charges seperated by 80 pm(pico+10^-12). How much work is required to turn the dipole from being aligned with the E fiield to be perpendicular to it? answer in electron volts

Explanation / Answer

part a)

Electric field at the protons position=E=F/e

where e is chareg on proton

part b)

since E is constant in between plates

and spacing between plates=d

so potential difference V=E/d

part c)

work done=change in potential energy

U=-pEcosa

in first case

a=0

in second case a=90

dU=0-(-pE)=pE

W=pE=qsE

q=e

s=10-12